y=(x^2-3x+2)(2x+4)

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Solution for y=(x^2-3x+2)(2x+4) equation: 


Simplifying
y = (x2 + -3x + 2)(2x + 4)

Reorder the terms:
y = (2 + -3x + x2)(2x + 4)

Reorder the terms:
y = (2 + -3x + x2)(4 + 2x)

Multiply (2 + -3x + x2) * (4 + 2x)
y = (2(4 + 2x) + -3x * (4 + 2x) + x2(4 + 2x))
y = ((4 * 2 + 2x * 2) + -3x * (4 + 2x) + x2(4 + 2x))
y = ((8 + 4x) + -3x * (4 + 2x) + x2(4 + 2x))
y = (8 + 4x + (4 * -3x + 2x * -3x) + x2(4 + 2x))
y = (8 + 4x + (-12x + -6x2) + x2(4 + 2x))
y = (8 + 4x + -12x + -6x2 + (4 * x2 + 2x * x2))
y = (8 + 4x + -12x + -6x2 + (4x2 + 2x3))

Combine like terms: 4x + -12x = -8x
y = (8 + -8x + -6x2 + 4x2 + 2x3)

Combine like terms: -6x2 + 4x2 = -2x2
y = (8 + -8x + -2x2 + 2x3)

Solving
y = 8 + -8x + -2x2 + 2x3

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Simplifying
y = 8 + -8x + -2x2 + 2x3

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